arrays - c (and objc, and c++ and objc++) - char* argv[] -
I am cloning the echo command and it is more complicated than what I was thinking. Here's my problem: A four * argv [] How does it work? I know how my string [] works, but there is no strange way to create a string:
- Is it an indicator of array of characters or array of characters? Why I * argv [n], it shows me n logic, not four char ... can cheers
behaves four argv [] such as
char ** argv will behave you a
Char argv [] [] can also be used in the same way.
By default, when you call
* argv , you should enter
Argv [0] and
* argv [n] gives
argv [0] [n]
edit: change
argv [x] a
std :: String in:
std :: string s (argv [x]);
s is a standard string at that point. But keep in mind that you should have a zero ended string, it's
four ** ! will not work for random binary data,
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