regex - How to remove the infront regular expression? -

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'http' या 'https' और 'www' को कैसे दूर करें, फिर 'google.com' पर छोड़ दिया जाए, '? 

  no_http_URL = regexp (domain_URL,' [az] +: // ',' match ',' one ')   
 उपरोक्त कोड मुझे परिणाम के लिए 'http' लौटाओ, जो मेरे उत्तर में उलटा है।   
 
 
  no_http_URL = Regexp ('http://google.com', 'https ?: // (?: Www।।)? (। *)', 'टोकन', 'एक बार') no_http_URL = regexp ('http: // www .google.com ',' https?: // (?: Www।)? (। *) ',' टोकन ',' एक बार ') no_http_URL = regexp (' https://google.com ',' https ?: // (?: Www।।)? (। *) ',' टोकन ',' एक बार ') no_http_URL = regexp (' https: //www.google.com ',' https?: // (? : Www।।)? (। *) ',' टोकन ',' एक बार ')   
  no_http_URL  के ऊपर अभिव्यक्ति में  1x1 सेल सरणी । यदि आपको स्ट्रिंग मान तक पहुंच की आवश्यकता है जिसे आपको निम्न निष्पादित करने की आवश्यकता है  
  no_http_URL = no_http_URL {1,1}

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