sorting - Sort a dict with date key in Python -

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मेरे पास दिनांक समय की कुंजी के साथ एक शब्द है 

  {u'2014-04 -21 14:46 ': {u'status': 0, u'created ': u'21-04-2014 14:46', u'duration ': u'0: 12'}, u'2014-04 -22 10:31 ': {यूस्टेट्स': 0, यू'केटेड ': यू'22-04-2014 10:31', यू-डैशन ': u'1: 28}}   
 मुझे उस तारीख समय की कुंजी के साथ सॉर्ट करने की आवश्यकता है।  
 मैंने पहले से नीचे की कोशिश की है जो कि इसमें उल्लेख है और यह अपेक्षित रूप से छंटनी नहीं कर रहा है।  
  आदेश दिया गया = आदेश दिया (सॉर्ट किया गया (mydict.items (), कुंजी = लैम्ब्डा टी: टी [0]))   
 उस प्रश्न में  2014-04-21  और मेरा  2014-04-21 14:46 ।  
 कोई भी सहायता सराहना करेगी।   
 
 
 जहाँ तक मैं अपने नमूना सेट से देख सकता हूँ, आप ISO दिनांक का उपयोग कर रहे हैं।  
 आईएसओ तारीखें हैं उनमें विशेष मामलों की तारीखों को संभालने की कोई आवश्यकता नहीं है। मैं आपके कोड में कुछ भी गलत नहीं देखता हूं।  
 अपना कोड चलाने के लिए, उदा।  
  & gt; & gt; & gt; सूची (क्रमबद्ध दिखे (क्रमबद्ध (mydict.items (), कुंजी = लैम्ब्डा टी: टी [0])))   
 सॉर्ट किए गए कुंजी उत्पन्न करता है, उदा।  <पूर्व>  [u'2014-04-21 14:46 ', यू'2014-04-22 10:31']   
 सूची को सॉर्ट करने के लिए  डिकिंग  आदेश में,  
  & gt; & gt; & gt; सूची (आदेश दिया गया (क्रमबद्ध (mydict.items), कुंजी = लैम्ब्डा टी: टी [0], उलट = सच)))

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