objective c - Why is BOOL turned to int when negated with explicit block return type -

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why BOOL , which four signed a typedef Is it changed when converted to int ? 

  does not // compile NSInteger events = [[contactCountries indexesOfObjectsPassingTest: ^ (id obj, NSUInteger IDX, BOOL * off) {return [isEqualIgnoringCase obj: @ "astring"]; }] Calculation];   
  Error:   
 
 to return type 'int' Back returns type 'BOOL' (aka 'signed four) should the block literally unspecified clear return type    
 
 
 that 'C' objective Due to ! C99 say  to about  operator (my emphasis): The 
 
 6.5.3.3 Single arithmetic operators, Article 5: 
 
 
 The result logical rejection operator! 0 if the value of its operand compares to 0 with the unequal, 1 if the value of its operand compares to 0 equals.  The result type is int.  Expression! E is equal to (0 == E.) 
 
 
 You put it: 
 
  return (bool) [isEqualIgnoringCase obj: @ "astring"];

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