compare - Java object compareto -

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  निजी तुलनात्मक [] आइटम = नया तुलनात्मक [1000000]; bubbleSort (आइटम); सार्वजनिक स्थैतिक & lt; टी तुलनात्मक विस्तारित & lt; T & gt; & gt; शून्य बबल सॉर्ट (टी [] सूची) {टी Temp; के लिए (int k = 1; k & lt; list.length; k ++) {// (इंट i = 0; i & lt; list.length - k; i ++) के लिए केथ पास करें {if (list [i] .compareTo (सूची [i + 1]) gt; 0) {temp = list [i]; सूची [i] = सूची [i + 1]; सूची [i + 1] = अस्थायी; }}}}   
 मुझे जो समस्या है वह  के साथ है (सूची [i] .compareTo (सूची [i]) & gt; 0) । मैंने सबकुछ टिप्पणी की है, एक समय में एक पंक्ति। यह केवल एक चीज है जो त्रुटि का कारण बनती है, और यह मुझे आउटपुट में स्पष्टीकरण नहीं देता। बस जो लाइनें है जो कि अगर होगा, और बुलबुला कोड को बुलाएगा।   
 
 
  निजी तुलनात्मक [] आइटम = नया तुलनात्मक [1000000];   
 यह पंक्ति सरणी में कोई भी तत्व प्रारंभ नहीं करता है। आपके पास प्रत्येक स्लॉट में  null  है, इसलिए आपका  NullPointerException ।  
 या हो सकता है कि आप इनिट कोड को पोस्ट न करें, लेकिन तब समस्या होगी ।

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