Convert day of the year to datetime in php -

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मेरे पास मूल्य है 

  $ days = 166.0444;   
 जो वर्ष का दिन है मैं इस वैल्यू को अपने डेटटाइम में कैसे परिवर्तित कर सकता हूं, जो  
  2013-06-15 01: 04: ss   
 होना चाहिए? निश्चित रूप से महीने में महीने की संख्या घटाने के लिए, महीने के साथ आगे बढ़ सकते हैं, और कुछ और रास्ता भी है, लेकिन क्या कोई अन्य तरीका है?  
 संपादित करें: वर्ष हमेशा चालू वर्ष होगा  
 धन्यवाद, हर कोई, मैंने ऐसा किया है:  <पूर्व>  $ dayOfYear = (int) $ परिणाम; $ Temp = ($ परिणाम - $ दिनअगर वर्ष) * 24; $ घंटे = (int) $ temp; $ Temp = ($ temp - $ घंटे) * 60; $ मिनट = (int) $ temp; $ Temp = ($ temp - $ मिनट) * 60; $ सेकंड = (इंट) $ अस्थायी; $ Date = नया दिनांकटाइम (); $ Date- & gt; जोड़ें (नया दिनांक इन्तरवर्ल्ड ('पी'। $ DayOfYear 'डी')); $ Date- & gt; जोड़ें (नया दिनांक अंतर ('पीटी'। $ घंटे। 'एच')); $ Date- & gt; जोड़ें (नया दिनांक अंतराल ('पीटी'। $ मिनट। 'एम')); $ Date- & gt; जोड़ें (नया दिनांक अंतर ('पीटी'। $ सेकंड। 'एस'));    
 
 
 आप इसे या इसी प्रकार से कर सकते हैं:  
  फ़ंक्शंस कन्वर्ट दिनटोडाडेटटाइम ($ दिन, $ वर्ष) {$ datetime = नया दिनांकटाइम (); वापसी $ datetime- & gt; सेटटिमस्टैम्प (एमकेटीएम (0,0,0,0,0,0, $ वर्ष) + $ दिन * 24 * 3600); } $ दिन = 166.0444; $ Datetime = convertDaysToDateTime ($ दिन, दिनांक ('वाई')); गूंज $ datetime- & gt; प्रारूप ('यू = वाई-एम-डी एच एच: आई: एस');

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