jquery - Can't get the value of input method val() -

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एक DIV है जिसमें इनपुट है:

यहां छवि विवरण दर्ज करें

ये लेआउट है: 

  & lt; div class =" input-daterange इनपुट -समूह afc "id =" datepicker-common-table "& gt; & lt; इनपुट प्रकार = "टेक्स्ट" वर्ग = "इनपुट-एसपी फॉर्म-कंट्रोल" नाम = "प्रारंभ" प्लेसहोल्डर = "Ð ?? Ð ° Ñ ?? Ð ° Ð" Ñ ?? нР° Ñ ?? Ð'Ð ° Ñ ​​?? Ð ° "& gt; & Lt; span class = "इनपुट-समूह-एडॉन" & gt; - & lt; / span & gt; & lt; इनपुट प्रकार = "टेक्स्ट" वर्ग = "इनपुट-एसपी फॉर्म-कंट्रोल" नाम = "एंड" प्लेसहोल्डर = "Ð ?? онÐμÑ ?? нР° Ñ ?? Ð'Ð ° Ñ ?? Ð °" & gt; & Lt; / div & gt;   
 ये स्क्रिप्ट है जो मूल्यों को स्थापित करने के बाद प्राप्त करने की कोशिश करता है:  
  $ (document) .on ('change', 'input [ Name = 'start'] ", फ़ंक्शन () {$ (दस्तावेज़) .on ('change', 'input [name =' end ']", फ़ंक्शन () {var startval = $ ("# datepicker-common-table & gt; इनपुट: टेक्स्ट ")। val (); var endVal = $ (" # datepicker-common-table & gt; इनपुट: टेक्स्ट ")। val (); console.log (startVal +" - "+ endVal);} );});   
 परिणामस्वरूप, कंसोल में निम्न आउटपुट प्राप्त होते हैं:  
  यहां छवि विवरण दर्ज करें    
 
 
 अपने स्क्रीनशॉट को देखते हुए, आपको < कोड> परिवर्तन दिनांक  घटना के साथ यह प्रदान करता है डेटा:  
  $ ("input [name = 'start']")। Datepicker ({})। ("ChangeDate" , फ़ंक्शन (ई) {var selectedDate = e.date; // event console.log से दिनांक मान प्राप्त करें ("दिनांक बदल गया", e.date);});   
 इसलिए, आपके उपयोग-केस के लिए (आप केवल जब  दोनों  चुने गए हैं तो लॉग इन करना चाहते हैं):  
  var दिनांक = {प्रारंभ: शून्य, अंत: शून्य}; $ ("। इनपुट-एसएएम")। तिथिपिकर ({प्रारूप: "डीडी-एमएम-याय", आजबीटीएन: "लिंक किया हुआ", भाषा: "एन", आजहाइटलाइट: सच, ऑटोक्लोस: सच})। ("परिवर्तनडेट" , समारोह (ई) {दिनांक [this.name] = e.date; अगर (dates.start और amp; date.end) {console.log ("दोनों तारीखों को चुना गया"); console.log (dates.start) ; Console.log (dates.end);}});

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