regex - correct pattern to change array values in bash -

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I need to strip 0 before all values ​​of an array, e.g. Change 

  array = (01 02 03 [...] 10 [...] 20 [...])   
 to  
  array = (1 2 3 [...] 10 [...] 20 [...])   
 I think I can do it together Can I get rid of the syntax? I have lost much of the syntax for $ {parameter / pattern / string} .  
  
 
 
 Given that it is an array of numbers, instead of trying to replace it string  arithmetic :  
  $ a = ({01.20}) $ "one dollar [one [@]}" $ icho "$ {a [@]}" $ 02 ($ 10 ($ 10) ($ 10 ($ 10)); $ $ Echo "$ {b [@ ]} "1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20   
 Here  $ ((10 # $ i))  variable  i  will be assessed as base 10 number.

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