java - How do you Specify a target directory for a txt file to be passed in -

-

Enter the code here I'm trying to specify a directory for a txt.file That which is being made when the jar file is played, is there any way to specify in the console as an argument where I want to make that TXT file:

The main Argument is: 

  public static zero main (string [] args) {// TODO automatically generated method Stub C: \ Users \ 802591720 \ document \ mystuff \ Programs \ JavaCode \ xmlSchema \ ManageBillingCreditAndDebit.20130219.xsd // string filename = "ManageBillingCreditAndDebit.20130219.xsd"; // string source = "c: \ user \ 607817544 \ as1 \"; String path 1 = args [0]; String filename = args [1]; TagDef tag def; String [] operation; {Operation = listOperationsUnique ("C: \\ User \\ 607817544 \\ as1 \\ ManageBillingCreditAndDebit.20130219.wsdl"); System.out.println ("Operation:" + operations.length); For (Int i = 0; I & lt; Operation. Lamper; I ++) {System.out.println ("Operation:" + Operation [i]); }} Hold (FileNotFoundException E) {// TODO auto generated blocking block e.printStackTrace (); } Grip (SAXException E) {// TODO Automatic generated block e.printStackTrace (); } Grip (IOException E) {// TODO Auto-Generated Catch Block e.printStackTrace (); } Hold (parser configuration exception e) {// Todo auto-generated catch block e.printStackTrace (); } {TagDef = refheader (path 1, filename); Println ("=============================================== ================== "); System.out.println ("Tag Description"); Println (tagDef); Println ("=============================================== ================== "); } Grip (Exception E) {// TODO Auto generated blocking block e.printStackTrace (); }   
}}  
 And this is the file's writing:  
  System.out.println (""); Fh.openFile ("hello.txt"); fh.writeLine (""); fh.closeFile ();   
 How do I go about specifying where to create that file in the console console?  
  
 
  
  
  
  
 Div class = "post -text "itemprop =" text "> 
 I suggest using the swing text field to open when you click on the jar, and after entering the path in the text field, submit the action that should be text Take data from the field and make further arguments.  
 So in this way the UI is a really good way to enter the path ..

Comments

Post a Comment

Popular posts from this blog

asp.net - Procedure or function "Procedure name" expects a parameter "Param name" which was not supplied occurs rarely -

-
I have a VB Net has a web service function that will send criteria to an SQL server stored function. Everything works perfectly for two months in the deployment machine. but now error The process or function GetEmployeeDetails is expected to have a parameter @progress which was not supplied 'P> posted on the machine Just came once. Everything works fine before and after the error. Web service code: public function GetLocation (ByVal as the oldNumber integer, ByVal integer as NewNumber, ByVal as the location string, Byval progress form In the form of a string, byVal name as string, byVal ID as string, try the string as Command1 = New SqlCommand ("GetEmployeeDetails" Connection1) with Command1. CommonType = CommandType Stored Surechers Parameter.ed ("@ old number", SQLDB type.int). Value = old number. Parameter.ed ("New Numer", SQLDB type.ins). Value = Newamer. Parameter. Add ("@Space", SQLBT Ype.VarChar, 10). Value = loc...
Read more

c# - The item with identity 'Id' already exists in the metadata collection. Parameter name: item -

-
मेरी सभी संस्थाओं का आधार वर्ग है: सार्वजनिक वर्ग इकाई & lt; TKey & gt; : आईएरिटीटी & lt; टीके & gt; {गतिशील आईईआरटीईटी.आईडी {प्राप्त करें} इस आईआईडी; } सेट {this.Id = मान; }} सार्वजनिक TKey Id {get; सेट; }} उदाहरण के लिए स्थिति इकाई: [मेटाडाटा टाइप (टाइपफ (स्टेटसमैटडेटा))] सार्वजनिक आंशिक श्रेणी की स्थिति: इकाई & lt; बाइट & gt; {सार्वजनिक स्ट्रिंग शीर्षक {प्राप्त करें; सेट; }} जब मैं डेटाबेस के विरुद्ध क्वेरी चलाऊँगा तो मुझे निम्न त्रुटि मिलती है: "पहचान 'आईडी वाला आइटम पहले से ही मेटाडेटा संग्रह में मौजूद है। पैरामीटर का नाम: आइटम" क्या यह तय करने का कोई तरीका है या यह किसी वारसा के कारण हुई समस्या है और मैं किसी भी वर्ग से अपनी संस्थाओं का वारिस नहीं कर सकता हूं? यह एक सामान्य त्रुटि है, कुछ जानकारी के लिए खोज करते हुए, मैंने देखा कि: दो तालिकाओं को एक प्राथमिक कुंजी के लिए एक ही नाम हो सकता है लाइटस्विच टेबल्स को देखो, उन सभी को एक प्राथमिक कुंजी है जिन्हें आईडी कहा जाता है। इसलिए, मैं सभी संस्थाओं की समीक्षा करता ह...
Read more

c++ - Redefined variable in the other module -

-
Why do we redefine the variable in other modules, so it is OK to add this module together? I have written two modules main.cpp and module.cpp as the following: // - main.cpp-- // # include & lt; Stdio.h & gt; Int main () {int i = 5; Printf ("I value is% d", i); } and // - module.cpp - // int i = 7; I am now compiling and adding g ++ as the following: g ++ -c main .cpp g ++ - c module. cao g ++ - o bin main.o module.o and it's okay. But I hope the compilation will be successful, while the linker will throw an exception like redefining varaible when I'm running .bin output then the value of i is 5 . UPD: I understand that if we use I as global variable module main.cpp that linker will throw an error. The main variable in the function is a local variable of i function. It is not visible and is present outside the function is. Consider the following example #include & lt; Iostream & gt; Int i = 3; Int main (...
Read more