string - Confusion in file functioning and append function using Python -

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मेरे पास परीक्षा के लिए दो प्रश्न हैं। 

  t2 = ("A", "   
 जवाब:    पूर्व>  कोई नहीं   
 मैंने सोचा था कि यह  [â € ??? Wilmaâ ????, (â € ??? ए, ????, एक होगा) ???? ???? ????, ????) हैलो ????)]   
 और  
 फ़ाइल में है:  
  जेम्स, 8 9 सोनिया, 7,6 क्लार्क, 4,5   
 कोड:  
  endofprogram = गलत प्रयास करें: infile = open ("Names.txt", â € œ râ ????) को छोड़कर IOError: print ("फ़ाइल पढ़ने में त्रुटि") endofprogram = true if endofprogram == गलत: infile में पंक्ति के लिए: line.strip ('\ n '' '' जेम्स '', '8', '9', ' क्यों नहीं '\ n' है ['सोनिया', '7', '6 \ n'] ['क्लार्क', '4', '5 \ n']   
 अभी तक वहीँ? निश्चित रूप से:  
  def बदलाव (aList): aList = aList.pop () aList.append (5) वापसी def main (): mylist = [1,2, [3]] परिवर्तन ( Mylist) प्रिंट (मेरीलिस्ट) मुख्य ()   
 उत्तर:  
  [1,2]   
 क्यों यह जवाब है?  [1,2,5]    
 
 
     < Li>  list.append  एक इन-प्लेस ऑपरेशन है, यह सूची को इन-प्लेस में संशोधित करता है और  None  देता है।   
      & gt; & gt; & gt; Lst = [] & gt; & gt; & gt; repr (lst.append (1)) # परत कोई नहीं 'कोई नहीं' & gt; & gt; & gt; lst #list संशोधित [1]   
       
    •  स्ट्रिंग्स अपरिवर्तनीय हैं, आपको  .strip ()  के परिणाम को पुन: असाइन करने की आवश्यकता है ।   
        line = line.strip ('\ n') # नई लौटा स्ट्रिंग को एक चर में पुन: असाइन करें। Alist = line.split (',')   
         
      •  आपको एक अलग सूची में फिर से असाइन किया गया  alist , इसलिए  .append ()  कॉल मूल रूप से पारित सूची को प्रभावित नहीं करेगा।   
          def बदलाव (aList): aList = aList.pop () # अब aList को इंगित करता है [3] नहीं आप केवल असाइनमेंट कथन का उपयोग यहां कर सकते हैं:  
          aList [1, 2, [3]] `aList.append (5)   
         -1] = 5

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