Recursion in Python without using a local/internal variable -

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I am not posting my exact problem in order to avoid space sake and confusion, but instead of identifying one I In the Python, print the sequence of numbers backwards. Restraint is that I should use recursion, and I should not have any local variables inside my function. For example, if the number 8 is given for the given function, then I want to print it 1,2,4,8. Also assume that the input is an integer, please. 

  def function (x) If (x! = 1) x = x / 2   
 I have dispelled my mind for a while, But I can not find anything that will actually print the final value (i can only achieve it to output 1,2,4)     
  def function (x) if (x! = 1) x = x / 2 function (x) print x,   
 code above 1,2,4 Prints, given that x is 8 in the beginning. However, if I put a recursive call anywhere in front of the "x = x / 2" line, then the value of x is constant 8  
 How can I accomplish everything I am trying to do? I'm sure there is something simple that I see, but I do not know how it is.  
 EDIT: Whoops, forgot to fill my print statement there.  
 Edit 2: Many thanks for both of you! Can not believe that this function calculates itself to avoid compiling the variable every time to calculate itself in the call.  
 Again, thanks a lot!   
 
 
 Everything is fine, but you really do not print anything. How (x! = 1): about function x (x / 2) print x      
  def (x)

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