Scala bring value into implicit scope without naming it -

When using, I inherent scope for each domain type JsonFormat [A] to get The requirement is A that I want to serial.

to create a custom object with all implicits as recommended approach fields:

  object MyJsonProtocol expansion DefaultJsonProtocol {contained Val colorFormat = jsonFormat4 (color)} import MyJsonProtocol._  

My app is a great many domain types, some of which have a long name. I MyJsonProtocol is getting long and unreadable:

  object MyJsonProtocol extends DefaultJsonProtocol {... // There are many more built-Val someClassWithALongNameFormat = jsonFormat4 (SomeClassWithALongName) built-Val SomeClassWithAlongNameInnerFormat = jsonFormat4 (SomeClassWithALongNameInner) built-in Val someClassWithALongNameVariantBFormat = jsonFormat4 (SomeClassWithALongNameVariantB) ... // here many more}  

There are various problems with long val name:

< Li> They feel nonsense (name is never read)
• They make my lines very long
• They introduce copy / paste risks that the name of the format will not match the format
• They do not combine the RHS values, which hide the same pattern

Is there any way to bring any object under the name? Something like this would be much neater:

  object MyJsonProtocol extends DefaultJsonProtocol {... // many lies more on val _ = jsonFormat4 (SomeClassWithALongName) underlying val _ = jsonFormat4 (SomeClassWithALongNameInner) underlying Val _ = JsonFormat4 (SomeClassWithALongNameVariantB) ... here many more}  

... but many fields named Scala are not allowed "_".

Is there any way to bring these formats without giving names to all? What is another way to use spray-json which avoids this problem? Typically, I define type-class examples of fellow objects:

{Class} Fus ​​(case) Fu {vested val jsonFormatter = new JsonFormat [fu] {...}} case class bar (object bar) {vested val jsonFormatter = new JsonFormat [bar] {...}} < / Code>

I do not have to import anything because fellow objects are included in the underlying search scope by default, and the underlying members can all have the same name.