python - Nested if; how to proceed to the next elif from true if -

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I'm learning "dragon hard way", my first programming language is also "block" inside the "if" block I'm trying to find out on the next "Alif" block.

I have written a small example: 

  door = raw_input ("& gt;") if door == "1": door == "2" alif door == "2": Printed "Red Yes."   
 Inside my actual code, if I block another if \ elif inside the "if" block, and inside one of them I would start an if \ elif condition I want to set up Alif, ie (Elif door == '2')  
 In the short example given above, I should have the output:  
 "& gt; 1 
 Lol yeah. "  
 I am sorry if that was not clear enough.   
 
 
 Try the following: <= P> 
  door = raw_input ("& gt; ; ") If door ==" 1 ": door =" 2 "if door ==" 2 ": print" lol yeah. "   
  if / elif  is conditional, it means that if  if  -clause is executed first, then  elif < / Code> is not reached.  
 Here's an example, I have a code in your code so that you can test it more easily.  
  & gt; & Gt; & Gt; Def test_doors (): ... door = raw_input ("& gt;") ... if door == "1": ... door = "2" ... if door == "2": .. Print "Red Yes." ... ... ... & gt; & Gt; & Gt; Test_doors () & gt; 1 Hello /   
 Note that if you have an error in your first  if  -clause, where you try to set the value of  door  Are  2 . You need to leave the second  = , otherwise the variables can never be changed. In fact, it is evaluated and the interpreter returns  wrong  because it thinks that you want to ask if  door  is of  2  Suppose you can try it in interpreter like this:  
  & gt; & Gt; & Gt; Door = 1> & Gt; & Gt; Doorway == 2 false & gt; & Gt; & Gt; Door == 1 true

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