php - Combine JSON array into single value -

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I am trying to insert several JS key key values ​​so that I can return only one value with all the data. For example, in my code, I want to add address 1, address2, address 3 to address Is it possible. I have tried several ways to experiment. = But anything seems to work. Gratefulness will be appreciated on any head. Thanks 

  $ query = "Select-from company_com"; = 0 to $; $ From = 30; $ Query = "LIMIT". $ From ",". $ To; $ Result = mysql_query ($ query) or die ("SQL Error 1:". Mysql_error ()); {$ Line = mysql_fetch_array ($ result, MYSQL_ASSOC)) {$ clients [] = array ('address1' => gt; $ line ['address1_com'], 'address2' = & gt; $ line ['address2_com '],' Address3 '= & gt; $ row [' address3_com ']); } Echo json_encode ($ clients);    
 
 
 You can type this very well ..  < Pre>  $ client = array (); $ I = =; $ Result = mysql_query ($ query) or die ("SQL Error 1:". Mysql_error ()); While ($ line = mysql_fetch_array ($ result, MYSQL_ASSOC)) {$ customers [$ i] ['address1'] = $ line ['address1_com']; $ Client [$ i] ['address2'] = $ line ['address2_com']; $ Client [$ i] ['address3'] = $ line ['address3_com']; $ I ++; } Echo json_encode ($ clients);   
 Changes made:  
     
  •  moved out of  $ client  array announcement  while  < / Li> 
  •  One flag  $ i = 0;  is set out of  .  
  •  The  $ client  array is made 2-dimensional, as you can see that the  $ i  key has been passed as a key.  
  •  Finally,  $ i  has increased.   
     
       edit:    
      & lt; Php $ customers = array (); $ I = =; $ Result = mysql_query ($ query) or die ("SQL Error 1:". Mysql_error ()); While ($ line = mysql_fetch_array ($ result, MYSQL_ASSOC)) {$ customers [$ i] ['address'] = $ line ['address1_com'] "". $ Line ['address2_com'] "". $ Line ['address3_com']; $ I ++; } Echo json_encode ($ clients);

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