How to replace the "?" using sed -

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I would like to know that ? Within a string using Sed % 53 .
I without success in CSS? has tried to avoid. Example: "string?" | Sed 's / \? /% 53 / g '. I tried \\? , [?], [\?], [\\?], \ X53 Is it also possible, using sed?

Simple quote between normaly directly without ASPA code (AiX / Bash / Pausix sed and cyan on GNU Test) probably with the -r option linux / bash / gnu sed 

  sed 's /? /% 53 / g on

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