How to concatenate a character constant into a string. C -

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If I have a constant character defined in C, can I include it in a line in the string ? 

  #ifdef WIN32 # define SEP '\\' #define ALTSEP '/' #sese # define SEP '/' #define ALTSEP '\\' #endif #define SOME_STRING_LITERAL "foo "/ * code snippet * / / * desired string:" prefix_fu / bar "* / const four * path =" prefix_ "SOME_STRING_LITERAL SEP" bar "; Of course, this fails because  sep  is not defined as a string, but there is no way to  sep  Insert? Or would I need any other definition, such as  #define SEP_STR "/" .   
 
 
 I do not think you can do it in C.  
 The main problem is that the  " symbol is something original that it knows the pre-processor should do or do it as a pre-processing token.  
 # Strings with operator will not help. Even if you  
  #define STRINGINIZE (X) #x #define CHAR_TO_STR (ch) STRINGINIZE (ch)  < / Pre> 
 and then open it as  
  const char * path = "prefix_" SOME_STRING_LITERAL; CHAR_TO_STR (SEP) "bar";   
 This will not be good for you, because you   
  prefix_ You can not do this by:  
  const char * path = "prefix_" SOME_STRING_LITERAL CHAR_TO_STR (SEP) [1] "foo` \ times   
 Bar ";   
 Because we had it in the first place and it will not be the ompili.  
 In addition to this, you do not have solution based on adding pre-processor tokens , Because  is more fundamental than "  ## .  
 So the only solution seems to declare the letter as string literals.

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